Terse Method to Swap Lowest for Highest?Efficient method for Inserting arrays into arraysSwap elements in list without copyBetter method to swap the values of two 2-D arraysHow to get this list with a terse methodBuilt-in (or Terse) Method to Combine and Transpose DatasetsAre there more readable and terse method can get this listefficiently method for generating a sequenceSimple method to sort versionsFunction for SortBySwap Elements of a continuous List, possible?

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Terse Method to Swap Lowest for Highest?


Efficient method for Inserting arrays into arraysSwap elements in list without copyBetter method to swap the values of two 2-D arraysHow to get this list with a terse methodBuilt-in (or Terse) Method to Combine and Transpose DatasetsAre there more readable and terse method can get this listefficiently method for generating a sequenceSimple method to sort versionsFunction for SortBySwap Elements of a continuous List, possible?













5












$begingroup$


I have built a solution to swap the lowest values with the highest values in a list.



With



SeedRandom[987]
test = RandomSample@*Join @@ Range @@@ 6, 10, 56, 60, 1, 5, -5, -1



-1, 2, 7, 8, 60, 57, 58, 10, 9, 4, -5, -3, 3, 59, 1, 5, -4, 6, -2, 56



Then



swapPositions =
PermutationReplace[
Ordering@Ordering@test,
With[len = Length@test,
Cycles@
Transpose@Range @@ 1, Floor[len/2], Reverse@*Range @@ Ceiling[len/2] + 1, len
]
];

Sort[test][[swapPositions]]



56, 9, 4, 3, -5, -2, -3, 1, 2, 7, 60, 58, 8, -4, 10, 6, 59, 5, 57, -1



The largest half of the numbers have had their positions swapped with lowest half of the numbers.



However, it feels too verbose and I think Sort might be expensive in this case. Is there a built-in function or more terse method to achieve this. Of course with no loss in speed. The actual case is for list of length 100000 and more.










share|improve this question











$endgroup$
















    5












    $begingroup$


    I have built a solution to swap the lowest values with the highest values in a list.



    With



    SeedRandom[987]
    test = RandomSample@*Join @@ Range @@@ 6, 10, 56, 60, 1, 5, -5, -1



    -1, 2, 7, 8, 60, 57, 58, 10, 9, 4, -5, -3, 3, 59, 1, 5, -4, 6, -2, 56



    Then



    swapPositions =
    PermutationReplace[
    Ordering@Ordering@test,
    With[len = Length@test,
    Cycles@
    Transpose@Range @@ 1, Floor[len/2], Reverse@*Range @@ Ceiling[len/2] + 1, len
    ]
    ];

    Sort[test][[swapPositions]]



    56, 9, 4, 3, -5, -2, -3, 1, 2, 7, 60, 58, 8, -4, 10, 6, 59, 5, 57, -1



    The largest half of the numbers have had their positions swapped with lowest half of the numbers.



    However, it feels too verbose and I think Sort might be expensive in this case. Is there a built-in function or more terse method to achieve this. Of course with no loss in speed. The actual case is for list of length 100000 and more.










    share|improve this question











    $endgroup$














      5












      5








      5





      $begingroup$


      I have built a solution to swap the lowest values with the highest values in a list.



      With



      SeedRandom[987]
      test = RandomSample@*Join @@ Range @@@ 6, 10, 56, 60, 1, 5, -5, -1



      -1, 2, 7, 8, 60, 57, 58, 10, 9, 4, -5, -3, 3, 59, 1, 5, -4, 6, -2, 56



      Then



      swapPositions =
      PermutationReplace[
      Ordering@Ordering@test,
      With[len = Length@test,
      Cycles@
      Transpose@Range @@ 1, Floor[len/2], Reverse@*Range @@ Ceiling[len/2] + 1, len
      ]
      ];

      Sort[test][[swapPositions]]



      56, 9, 4, 3, -5, -2, -3, 1, 2, 7, 60, 58, 8, -4, 10, 6, 59, 5, 57, -1



      The largest half of the numbers have had their positions swapped with lowest half of the numbers.



      However, it feels too verbose and I think Sort might be expensive in this case. Is there a built-in function or more terse method to achieve this. Of course with no loss in speed. The actual case is for list of length 100000 and more.










      share|improve this question











      $endgroup$




      I have built a solution to swap the lowest values with the highest values in a list.



      With



      SeedRandom[987]
      test = RandomSample@*Join @@ Range @@@ 6, 10, 56, 60, 1, 5, -5, -1



      -1, 2, 7, 8, 60, 57, 58, 10, 9, 4, -5, -3, 3, 59, 1, 5, -4, 6, -2, 56



      Then



      swapPositions =
      PermutationReplace[
      Ordering@Ordering@test,
      With[len = Length@test,
      Cycles@
      Transpose@Range @@ 1, Floor[len/2], Reverse@*Range @@ Ceiling[len/2] + 1, len
      ]
      ];

      Sort[test][[swapPositions]]



      56, 9, 4, 3, -5, -2, -3, 1, 2, 7, 60, 58, 8, -4, 10, 6, 59, 5, 57, -1



      The largest half of the numbers have had their positions swapped with lowest half of the numbers.



      However, it feels too verbose and I think Sort might be expensive in this case. Is there a built-in function or more terse method to achieve this. Of course with no loss in speed. The actual case is for list of length 100000 and more.







      list-manipulation performance-tuning sorting






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 1 hour ago









      m_goldberg

      87.7k872198




      87.7k872198










      asked 1 hour ago









      EdmundEdmund

      26.7k330102




      26.7k330102




















          1 Answer
          1






          active

          oldest

          votes


















          8












          $begingroup$

          How about:



          Module[tmp = test,
          With[ord=Ordering[tmp],
          tmp[[ord]] = Reverse @ tmp[[ord]]];
          tmp
          ]



          56, 9, 4, 3, -5, -2, -3, 1, 2, 7, 60, 58, 8, -4, 10, 6, 59, 5, 57, -1







          share|improve this answer









          $endgroup$












          • $begingroup$
            That is so obvious I want to cry. Thanks (+1).
            $endgroup$
            – Edmund
            1 hour ago










          Your Answer





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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          8












          $begingroup$

          How about:



          Module[tmp = test,
          With[ord=Ordering[tmp],
          tmp[[ord]] = Reverse @ tmp[[ord]]];
          tmp
          ]



          56, 9, 4, 3, -5, -2, -3, 1, 2, 7, 60, 58, 8, -4, 10, 6, 59, 5, 57, -1







          share|improve this answer









          $endgroup$












          • $begingroup$
            That is so obvious I want to cry. Thanks (+1).
            $endgroup$
            – Edmund
            1 hour ago















          8












          $begingroup$

          How about:



          Module[tmp = test,
          With[ord=Ordering[tmp],
          tmp[[ord]] = Reverse @ tmp[[ord]]];
          tmp
          ]



          56, 9, 4, 3, -5, -2, -3, 1, 2, 7, 60, 58, 8, -4, 10, 6, 59, 5, 57, -1







          share|improve this answer









          $endgroup$












          • $begingroup$
            That is so obvious I want to cry. Thanks (+1).
            $endgroup$
            – Edmund
            1 hour ago













          8












          8








          8





          $begingroup$

          How about:



          Module[tmp = test,
          With[ord=Ordering[tmp],
          tmp[[ord]] = Reverse @ tmp[[ord]]];
          tmp
          ]



          56, 9, 4, 3, -5, -2, -3, 1, 2, 7, 60, 58, 8, -4, 10, 6, 59, 5, 57, -1







          share|improve this answer









          $endgroup$



          How about:



          Module[tmp = test,
          With[ord=Ordering[tmp],
          tmp[[ord]] = Reverse @ tmp[[ord]]];
          tmp
          ]



          56, 9, 4, 3, -5, -2, -3, 1, 2, 7, 60, 58, 8, -4, 10, 6, 59, 5, 57, -1








          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 1 hour ago









          Carl WollCarl Woll

          71.2k394185




          71.2k394185











          • $begingroup$
            That is so obvious I want to cry. Thanks (+1).
            $endgroup$
            – Edmund
            1 hour ago
















          • $begingroup$
            That is so obvious I want to cry. Thanks (+1).
            $endgroup$
            – Edmund
            1 hour ago















          $begingroup$
          That is so obvious I want to cry. Thanks (+1).
          $endgroup$
          – Edmund
          1 hour ago




          $begingroup$
          That is so obvious I want to cry. Thanks (+1).
          $endgroup$
          – Edmund
          1 hour ago

















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